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What is the remainder when the base-$12$ integer $20130118_{12}$ is divided by $8$? Write your answer in base $10$.

 Sep 30, 2022
 #1
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20130118 = 

 

12^2=144= 0 mod 8

therefore 12 ^ anynumber greater than 2 is also 0 mod 8

 

so   

 

     \(20130118_{12}\;\mod8 \\ = 18_{12}\mod8\\ =20_{10}\mod10 \\ =4\)

 Oct 1, 2022
edited by Melody  Oct 1, 2022

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