What is the remainder when the base-$12$ integer $20130118_{12}$ is divided by $8$? Write your answer in base $10$.
20130118 =
12^2=144= 0 mod 8
therefore 12 ^ anynumber greater than 2 is also 0 mod 8
so
\(20130118_{12}\;\mod8 \\ = 18_{12}\mod8\\ =20_{10}\mod10 \\ =4\)
