In triangle $XYZ$, the bisector of $\angle YXZ$ meets $\overline{YZ}$ at $W.$ If $\angle YXZ = 60^\circ,$ $\angle Y = 45^\circ,$ and $XW = 24,$ then find the area of triangle $XYZ$.
The area of triangle ABC is 24 + 144*sqrt(3).
Oh yeah, I meant XYZ.
