Which value of x makes the equation true?
Cross-multiplication.
\(6(3x-6)=3(7x-3)\)
Divide both sides by 3
\(2(3x-6)=(7x-3)\)
Expand left bracket
\(6x-12=7x-3\)
Add 12
\(6x=7x+9\)
subtract 6x
\(x+9=0\)
Subtract 9
\(x=-9\)
