In a certain isosceles right triangle, the altitude to the hypotenuse has length $4\sqrt{2}$. What is the area of the triangle?

Guest Oct 26, 2019

#1**+1 **

Right isosceles triangle.

Sides: a = 8 b = 8 c = 11.314

**Area: T = 32**

Perimeter: p = 27.314

Semiperimeter: s = 13.657

Angle ∠ A = α = 45° = 0.785 rad

Angle ∠ B = β = 45° = 0.785 rad

Angle ∠ C = γ = 90° = 1.571 rad

Height: ha = 8

Height: hb = 8

Height: hc = 5.657

Guest Oct 26, 2019

#2**+1 **

Here is a formula :

A = x^2

Where x represents the distance from altitude to the hypotenuse.

In this case it is \(4\sqrt{2}\).

So the area is 32

CalculatorUser
Oct 26, 2019