In a certain isosceles right triangle, the altitude to the hypotenuse has length $4\sqrt{2}$. What is the area of the triangle?
Right isosceles triangle.
Sides: a = 8 b = 8 c = 11.314
Area: T = 32
Perimeter: p = 27.314
Semiperimeter: s = 13.657
Angle ∠ A = α = 45° = 0.785 rad
Angle ∠ B = β = 45° = 0.785 rad
Angle ∠ C = γ = 90° = 1.571 rad
Height: ha = 8
Height: hb = 8
Height: hc = 5.657
+2862 Here is a formula :
A = x^2
Where x represents the distance from altitude to the hypotenuse.
In this case it is \(4\sqrt{2}\).
So the area is 32
