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# Plzzz help ASAP

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In a certain isosceles right triangle, the altitude to the hypotenuse has length $4\sqrt{2}$. What is the area of the triangle?

Oct 26, 2019

#1
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Right isosceles triangle.

Sides: a = 8   b = 8   c = 11.314

Area: T = 32
Perimeter: p = 27.314
Semiperimeter: s = 13.657

Angle ∠ A = α = 45° = 0.785 rad
Angle ∠ B = β = 45° = 0.785 rad
Angle ∠ C = γ = 90° = 1.571 rad

Height: ha = 8
Height: hb = 8
Height: hc = 5.657

Oct 26, 2019
#2
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Here is a formula :

A = x^2

Where x represents the distance from altitude to the hypotenuse.

In this case it is $$4\sqrt{2}$$.

So the area is 32

CalculatorUser  Oct 26, 2019
edited by CalculatorUser  Oct 26, 2019
#3
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I believe guest proved the formula

CalculatorUser  Oct 26, 2019