plzzz help surface area of a tissue box

9¾ + 4¾ + 3/10 + 3/10

 

\(9\frac34 + 4\frac34 +\frac3{10}+ \frac3{10} \\~\\ = \frac{39}{4} + \frac{19}{4} + \frac3{10}+ \frac3{10} \\~\\ = \frac{390}{40} + \frac{190}{40} + \frac{12}{40}+ \frac{12}{40} \\~\\ = \frac{390 +190+12+12}{40} = \frac{604}{40} = \frac{151}{10} = 15.1\)