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Find the points of discontinuity in: y=(2x^2 + 5)/(x^2 - 2x) help please.
Guest May 1, 2012
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everywhere where x^2 - 2x = 0

[input]x^2 - 2x=0[/input]

[input]plot( (2x^2 + 5)/(x^2 - 2x) , -1..3, -100..100 )[/input]
admin  May 1, 2012

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