Points $A$, $B$, and $C$ are on a circle such that $AB = 8$, $BC = 15$, and $AC = 12$. Find the radius of the circle.
The perpendicular bisectors of each side meet at D = (6 , 4.55)
The radius of the circle = sqrt ( 6^2 + 4.55^2) = sqrt ( 56.7025)
+816 
