Assume that in each pair of figures, the second polygon is similar to the first, with the same orientation. Perform these steps.
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Can someone please solve them if my work is right? Thanks.
+128407 1. We have that
6/9 = t / [ t + 2 ] cross-multiply
6 [ t + 2] = 9t
6t + 12 = 9t subtract 6t from both sides
12 = 3t divide both sides by 3
4 = t
t + 2 = 6
We can find the missing side S of the figure on the right, thusly
11/9 = S /[ t + 2]
11/9 = S / 6 cross-multiply
11* 6 = 9S
66 = 9S divide both sides by 9
66/9 = S = 22/3
+128407 2.
6/8 = [ w - 5 ] / w cross-multiply
6w = 8 [ w - 5 ]
6w = 8w - 40 subtract 8w from both sides
-2w = -40 divide both sides by -2
w = 20
w - 5 = 15
To find one missing side in the second figure that would be the couter-part to the side of 9 in the first figure we have that
Missing side/ w = 9/8
Missing side 20 = 9/8 multiply both sides by 20
Missing side = 20 * 9 / 8 = 180 / 8 = 22.5
And to find the last missing side of the second figure that is a counter-part to the side of 14 in the first figure we have that
Missing side / 22.5 = 14/ 9
Missing side = 22.5 * 14 / 9 = 35
+128407 3.
t/ 4 = [ t + 1 ] / 6 cross-multiply
6t = 4 [ t + 1 ]
6t = 4t + 4 subtract 4t from both sides
2t = 4 divide both sides by 2
t = 2
t + 1 = 3
To find the remaining missing side in the first figure we have that
Missing side / t = 10/ [ t + 1 ]
Missing side / 2 = 10/ 3
Missing side = 2 * 10 / 3 = 20/3
