Find the remainder when x^4 + 1 is divided by x^2 - 3x + 6.
x^2 + 3x + 3
x^2 -3x + 6 [ x^4 + 0x^3 + 0x^2 + 0x + 1 ]
x^4 - 3x^3 + 6x^2
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3x^3 - 6x^2 + 0x
3x^3 - 9x^2 + 18x
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3x^2 - 18x + 1
3x^2 - 9x + 18
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-9x - 17 = the remainder
