If $(x + 2)(3x^2 - x + 5) = Ax^3 + Bx^2 + Cx + D$, what is the value of $A + B + C + D$?
(x + 2)(3x2 - x + 5)
= 3x3 - x2 + 5x + 6x2 - 2x + 10
= 3x3 + 5x2 + 3x + 10
A = 3
B = 5
C = 3
D = 10
A + B + C + D = 3 + 5 + 3 + 10 = 21, which is your answer :)