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If $(x + 2)(3x^2 - x + 5) = Ax^3 + Bx^2 + Cx + D$, what is the value of $A + B + C + D$?

 Feb 14, 2021
 #1
avatar+592 
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(x + 2)(3x2 - x + 5)

 

= 3x3 - x2 + 5x + 6x2 - 2x + 10

 

= 3x+ 5x2 + 3x + 10

A = 3

B = 5

C = 3

D = 10

 

A + B + C + D = 3 + 5 + 3 + 10 = 21, which is your answer :)

 Feb 14, 2021

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