Let f(x)=3x^4-7x^3-2x^2-bx+1. For what value of b is f(1)=1
For what value of b is f(1)=1?
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\(f(1)=3x^4-7x^3-2x^2-({\color{blue}-6})\cdot x+1=1\)
For the value of b = - 6 is f(1) = 1.
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