P(x) = 2x^4 - x^3 + 2x^2 - k where k is an unknown integer. P(x) divided by (x+1) has a remainder of 2. What is the value of k?
+14913 P(x) = 2x^4 - x^3 + 2x^2 - k where k is an unknown integer. P(x) divided by (x+1) has a remainder of 2. What is the value of k?
Hello Guest!
P (x) = 2x ^ 4 - x ^ 3 + 2x ^ 2 - k wobei k eine unbekannte ganze Zahl ist. P (x) geteilt durch (x + 1) hat einen Rest von 2. Was ist der Wert von k?
\(P_v(x) =\frac{ 2x^4 - x^3 + 2x^2 - k }{x+1}\)
\( 2x^4 - x^3 + 2x^2 - k :{\color{blue}(x+1)}=\)\(2x^3-3x^2+4x-\frac{k}{x}-\ ...\)
\(\underline{2x^4+2x^3}\)
\(-3x^3-2x^2\)
\(\underline{-3x^3-3x^2}\)
\(5x^2-k\)
\(\underline{5x^2+4x}\)
\(-k-4x\)
\(\large\frac{{\color{blue}2}-k-4x}{x+1}=\color{blue}\mathbb Z\)
will be added.
