Let f(x)=3x^4-7x^3-2x^2-bx+1. For what value of b is f(1)=1
Just put '1' in for 'x' and calculate 'b'
3 (14) - 7 (13) - 2(12) - b (1) + 1 = 1 solve for 'b'
+36916 
