If f(x) is a monic quartic polynomial such that f(-1) = -1, f(2) = -4, f(3) = -9, and f(4) = -16, find f(1).
f(x)+x^2= (x+1)(x-2)(x+3)(x-4)
f(1)=2*(-1)*4*(-3)-1^2=23
JP
