+36916 For quadratic Formula
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
a = 3 b=-12 and c = -663
You can simplify the math.....and maybe see 'in your mind' if you can factor it by first dividing the left and right sides of the equation by 3 to get
x^2 - 4x - 221 =0
Doesn't help me much
use the QF
a = 1 b= -4 c= -221
4+-sqrt(16-4(1)(-221) / 2 = 4+- 30 / 2 ========> 17 or -13
SO factoring would look like (x-17)(x+13) = 0
