We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
138
1
avatar

Please help, thanks.

 

 Oct 29, 2018
 #1
avatar+18293 
+1

For quadratic Formula

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

 

a = 3  b=-12 and c = -663

 

You can simplify the math.....and maybe see 'in your mind' if you can factor it by first dividing the left and right sides of the equation by 3 to get

x^2 - 4x - 221 =0

     Doesn't help me much

        use the QF 

            a = 1 b= -4 c= -221  

 

4+-sqrt(16-4(1)(-221)   /  2   =     4+- 30   /  2   ========>   17    or   -13

 

SO factoring would look like    (x-17)(x+13) = 0

 Oct 29, 2018

8 Online Users