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Find the constant t such that
(5x^2 - 6x + 7)(4x^2 + tx + 10) = 20x^4 - 9x^3 + 60x^2 - 39x + 70

 Aug 5, 2021
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For the 'x'  portion    -6x(10)  + 7t x = - 39 x

                                    -60 x + 7tx = - 39x

                                                 7tx = 21x

                                                    t = 3

 Aug 5, 2021

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