Find the constant t such that (5x^2 - 6x + 7)(4x^2 + tx + 10) = 20x^4 - 9x^3 + 60x^2 - 39x + 70
For the 'x' portion -6x(10) + 7t x = - 39 x
-60 x + 7tx = - 39x
7tx = 21x
t = 3