#1**+2 **

How many positive integer divisors of 23,328 are perfect cubes?

23328^(1/3) = 28.573218935427587 Well less than 29 anyway.

1 is ok

factor(23328) = 2^5*3^6

\(2*2*2*2*2\quad * \quad 3*3*3*3*3*3\\~\\ 1^3,2^3,3^3,6^3,9^3,18^3 \;\;\text{that seems to be it.} \)

I just got those from visual examination of the factors.

So that is 6 of them.

Melody Dec 24, 2018