The difference between two positive integers is $6$ and their product is $40$. What is the sum of the integers?
10 and 4
x - y = 6 so y = x-6
x ( x-6) = 40
x^2 - 6x -40 = 0
(x-10)(x + 4) =0 shows the positive answer for x = 10 then the other is 10 - 6 = 4