The value of (1 + i)^16 is a positive real number. What is it?
Simplify the following: (i + 1)^16
(1 + i)^16 = ((i + 1)^8)^2 = (((i + 1)^4)^2)^2 = ((((i + 1)^2)^2)^2)^2: ((((i + 1)^2)^2)^2)^2
(i + 1)^2 = 1 + i + i - 1 = 2 i: (((2 i)^2)^2)^2
(2 i)^2 = -4: ((-4)^2)^2
(-4)^2 = 16: 16^2
=256