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Potenzieren
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670
2
Jo hab mal ne frage zum potenzieren.Also (1/n)^-1 ist ja n.
Aber wieso? Bei 1/5 müsste man doch mit 1/5 dividieren oder?Dann würde man aber auf 1 kommen.
Bei einer multiplikation würde man ja auf 0.04 kommen....Bin ich dumm xD ?
Guest
Nov 7, 2012
2
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Answers
#1
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Hat sich erledigt nur n muss potenziert werden nicht der gesamte bruch
Guest
Nov 7, 2012
#2
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hi,
auch wenn der gesamte Bruch potenziert werden muss, eine Potenz von -1 dreht den Bruch um.
Also (1/n)^-1 = n
(1/5)^-1 = 5
Guest
Nov 9, 2012
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