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If the mean (average) of five consecutive integers is $21,$ what is the smallest of the five integers?

 Mar 19, 2020

Best Answer 

 #1
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The consecutive integers are:  x,  x +1,  x + 2,  x + 3, x + 4

The mean of these integers is:  x + 2

Since the mean is 21:  x + 2  =  21

which means that x (which is the smallest) is 19.

 Mar 19, 2020
 #1
avatar+20802 
+2
Best Answer

The consecutive integers are:  x,  x +1,  x + 2,  x + 3, x + 4

The mean of these integers is:  x + 2

Since the mean is 21:  x + 2  =  21

which means that x (which is the smallest) is 19.

geno3141 Mar 19, 2020

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