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A right triangle has an acute angle x such that cot(x)=5. find csc(x).

I know the answer is sqroot of 26. Though I dont understand how

 Apr 26, 2015

Best Answer 

 #1
avatar+126679 
+5

If cot(x)  = 5, we have  x/y  = 5/1

So 

r = √[5^2 + 1^2] = √[25 + 1 ] = √26

And csc(x) = r / y = √26  / 1   =  √26

 

  

 Apr 26, 2015
 #1
avatar+126679 
+5
Best Answer

If cot(x)  = 5, we have  x/y  = 5/1

So 

r = √[5^2 + 1^2] = √[25 + 1 ] = √26

And csc(x) = r / y = √26  / 1   =  √26

 

  

CPhill Apr 26, 2015

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