Pre-calc question

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708

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A right triangle has an acute angle x such that cot(x)=5. find csc(x).

I know the answer is sqroot of 26. Though I dont understand how

Guest Apr 26, 2015

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Best Answer

+128406

+5

If cot(x) = 5, we have x/y = 5/1

So

r = √[5^2 + 1^2] = √[25 + 1 ] = √26

And csc(x) = r / y = √26 / 1 = √26

CPhill Apr 26, 2015

1⁺⁰ Answers

+128406

+5

Best Answer

If cot(x) = 5, we have x/y = 5/1

So

r = √[5^2 + 1^2] = √[25 + 1 ] = √26

And csc(x) = r / y = √26 / 1 = √26

CPhill Apr 26, 2015

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