+0  
 
-1
153
1
avatar+318 

A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. If the area of the pool and the path combined is 896 square meters, what is the width of the path?

 Feb 10, 2020
 #1
avatar+111389 
+1

Let the width of the path  = W

 

So we have that

 

(18 + 2W) ( 22 + 2W)  =  896      simplfy

 

396  + 44W + 36W  + 4W^2  =  896

 

4W^2  + 80W + 396  = 896     subtract 896 from both sides

 

4W^2  + 80W  - 500  = 0       divide through by 4

 

W^2  + 20W  -  125   = 0       factor as

 

(W - 5) ( W + 25)  = 0

 

Setting each  factor to 0  and solving for W produces  W = 5    or W  = -25

 

Obviously....only the positive answer makes sense....so...

 

The width of the path  = 5 ft

 

 

cool cool cool

 Feb 10, 2020

13 Online Users

avatar
avatar