A pool measuring 18 meters by 22 meters is surrounded by a path of uniform width. If the area of the pool and the path combined is 896 square meters, what is the width of the path?

mharrigan920 Feb 10, 2020

#1**+1 **

Let the width of the path = W

So we have that

(18 + 2W) ( 22 + 2W) = 896 simplfy

396 + 44W + 36W + 4W^2 = 896

4W^2 + 80W + 396 = 896 subtract 896 from both sides

4W^2 + 80W - 500 = 0 divide through by 4

W^2 + 20W - 125 = 0 factor as

(W - 5) ( W + 25) = 0

Setting each factor to 0 and solving for W produces W = 5 or W = -25

Obviously....only the positive answer makes sense....so...

The width of the path = 5 ft

CPhill Feb 10, 2020