Determine
lim | x-3 | / x^2 - 9
x -> 3
a. limit does not exist
b. 0
c. 3
d. 1/6
e. -1/6
We can write the ratio as |x - 3|/((x - 3)(x + 3))
As x → 3 from above |x - 3| is just x - 3 , so the ratio becomes 1/(x + 3) or 1/6
As x → 3 from below |x - 3| is 3 - x, so the ratio becomes -1/(x + 3) or -1/6
.
See graph:
Hi, I am the one who wrote this post and I did not write the comment above. Just wanted to make sure you all know that that was not me. Thank you for helping me Alan!
