We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
47
3
avatar+211 

 

Solve the equation over the interval [0,2pie), stating answers in radians

 Mar 10, 2019
 #1
avatar+99441 
+2

sin^2x - 2sin x + 1  = 0        factor as

 

(sin  x - 1) (sin x - 1) = 0

 

Either factor will give the same solution

 

sin x - 1  =   0

 

sin x = 1

 

arcsin (1)  = x  =  pi/ 2

 

 

cool  cool cool

 Mar 10, 2019
 #2
avatar+211 
+1

Thank you! smiley

Cupcake  Mar 10, 2019
 #3
avatar+99441 
+1

No prob  !!!

 

cool cool cool

CPhill  Mar 10, 2019

10 Online Users