Solve the equation over the interval [0,2pie), stating answers in radians
sin^2x - 2sin x + 1 = 0 factor as
(sin x - 1) (sin x - 1) = 0
Either factor will give the same solution
sin x - 1 = 0
sin x = 1
arcsin (1) = x = pi/ 2
Thank you!
No prob !!!
+315 
