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hi! I have a question that i need to be double checked

 

Kirsten stands in her backyard and watches two cats. First, she looks to her cat. Her cat is 100 feet away from her.

She turns 115° and views her neighbor's cat. The neighbor's cat is 60 feet away from her.

How far apart are the cats?

Enter your answer, rounded to the nearest tenth of a foot, in the box.

 

I think the answer is either 116.6, or 6000.4. I think the first one makes more sense though. Thank you so much for answering! I really appreciate it!

 Apr 20, 2020
 #1
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+2

hello,
i used law of cosines where
a = 100, b = 60, and C(angle opposite of side c) = 115°

(little visualization)


c2=a2+b2-2abcosC
c2=18671.419
(sqrt the c^2)
c = 136.6 ft

 Apr 20, 2020
 #2
avatar+26007 
+1

 I get  136.64 ft

 Apr 20, 2020

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