+74 State the amplitude , period, phase shift, and vertical shift of y=sin (4x + pi) - 1.
+118628 State the amplitude , period, phase shift, and vertical shift of y=sin (4x + pi) - 1.
y=sin (4x + pi) - 1
\(y+1=1sin [4 (x +\frac{ pi}{4})] \\ Amplitude=1\\ period=\frac{2\pi}{4}=\frac{\pi}{2}\\ \mbox{phase shift is given by the solution to}\\ x +\frac{ pi}{4}=0\\ x= -\frac{ pi}{4}\\ \mbox{Vertical displacement is given by the solution to }\\ y+1=0\\ y=-1\qquad \mbox{The centre of the oscillation will be }y=-1\)
