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f tan α = 1/10 and tan β = 9/11, find α + β, given that 0 < α < π/2 and 0 < β < π/2.
 Oct 17, 2013
 #1
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As far as I understand the question, you simply have to calculate
\alpha and
\beta via the corresponding inverse function, meaning atan(1/10)/atan(9/11). You then need to convert, if not already, the result into radian and add it. As tan() is a periodic function, make sure that you result lies in the given interval.
 Oct 17, 2013
 #2
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I haven't finished it but you start by using the identity

tan(a+b) = [tan(a) +tan(b)] / [1- tan(a)tan(b)]

Do the substitution, then use arc sin
dont forget to consider the angle restrictions.
 Oct 17, 2013

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