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In triangle ABC, \(\angle C = 90^\circ\)  and M is the midpoint of \(\overline{BC}\) If \(\sin \angle BAM = \frac{1}{3},\) then what is \(\sin \angle BAC\)?

 Jul 29, 2022
 #1
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Good question!  sin BAC = sqrt(7)/3.

 Jul 29, 2022
 #2
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how do you know?

 

CPHILL HEEEELP

brainiac  Jul 29, 2022
 #3
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I drew a diagram, and worked it out.  My friend got the same answer.

Guest Jul 29, 2022
 #4
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well, its wrong

brainiac  Jul 29, 2022

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