In triangle ABC, \(\angle C = 90^\circ\) and M is the midpoint of \(\overline{BC}\) If \(\sin \angle BAM = \frac{1}{3},\) then what is \(\sin \angle BAC\)?
Good question! sin BAC = sqrt(7)/3.
how do you know?
CPHILL HEEEELP
I drew a diagram, and worked it out. My friend got the same answer.
well, its wrong
+44 
