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What's the matrix that rotates vectors by pi/6 counterclockwise?

 Oct 9, 2019

Best Answer 

 #1
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\(R(\theta) = \begin{pmatrix}\cos(\theta)&-\sin(\theta)\\\sin(\theta)&\cos(\theta)\end{pmatrix}\\ \text{Now just plug in $\theta=\dfrac{\pi}{6}$}\)

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 Oct 9, 2019
edited by Rom  Oct 10, 2019
 #1
avatar+6017 
+1
Best Answer

\(R(\theta) = \begin{pmatrix}\cos(\theta)&-\sin(\theta)\\\sin(\theta)&\cos(\theta)\end{pmatrix}\\ \text{Now just plug in $\theta=\dfrac{\pi}{6}$}\)

 
Rom Oct 9, 2019
edited by Rom  Oct 10, 2019

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