a varies inversely as b^3. If a=9/2 when b=2, find a when b is 3
PLEASE HELP could not solve at all
a = k/b^3 sub in a = 9/2 and b = 2 to find k
9/2 = k / 8
k = 36
a = 36/b^3
= 36/33 = 36/27 = 1 1/3
+318 
+36916 
