costheta=-(sqrt(3)/4), where pi
tanB=3/4, where 0
What is the exact value of sin(theta+B)?
Answer in simplified fraction form.
*I also included a picture of the problem*
**PLEASE HELP!!!**
+128474 sin ( θ + B) = sin θ cos B + sin B cos θ
sin θ = - sqrt [ 4^2 - (sqrt (3))^2 ] / 4 = - sqrt [ 16 - 3 ]/4 = -sqrt (13) / 4
sin B = 3 /sqrt (3^2 + 4^2) = 3 / sqrt 25 = 3/5
cos B = = 4 / sqrt ( 3^2 + 4^2) = 4 / sqrt 25 = 4/5
So
sin ( θ + B) = sin θ cos B + sin B cos θ =
-sqrt (13) / 4 * 4/5 + 3/5 * -sqrt (3) / 4 =
-4sqrt (13) - 3sqrt (3)
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