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In triangle ABC show above, cos B = 6/10. What is tan C?

 

 Jan 22, 2021
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In triangle ABC show above, cos B = 6/10. What is tan C?

 

Hello Guest!

 

\(c^2=a^2+b^2-2ab\cdot cos\ C\\ cos\ C=\dfrac{a^2+b^2-c^2}{2ab}\\ cos\ C=\dfrac{49+32-25}{56\cdot \sqrt{2}}=\dfrac{1}{\sqrt{2}}\)

\(C=\arccos\ \dfrac{1}{\sqrt{2}}\)

\(C=45°\)

\(tan\ C=tan 45°\)

\(tan\ C=1\)

laugh  !

 Jan 22, 2021

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