Two ships leave an island at the same time. One of them travels north-west at an average speed of 10.5 km/h while the other travels at an average speed of 14 km/h on a bearing of 280ᐤ. How far apart are these ships after 2 hours?
+36916 Northwest is 315o
Start at oigin 0,0 find components of north and west for each
A 2 hours 2 * 10.5 * sin 315 =14.85 W
2 * 10.5 * cos 315 = 14.85 N
B 2 hours 28 sin 280 = 27.57 W
28 cos 280 = 4.86 N
Ship A is |14.85 - 4.86| = 9.99 N-S km
and |14.85 - 27.57| = 12.72 W-E km of ship B Pythag theorem sqrt (12.72^2 + 9.99^2) = 16.17 km apart
(I hope I did that correctly! 
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