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how do I find 
\(tan^2\theta\)

\(sin^2\theta \)\(cos^2\theta \)

brkr19  Feb 27, 2017
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3+0 Answers

 #1
avatar+76953 
0

Are you dividing these, brkr19 ???

 

cool cool cool

CPhill  Feb 27, 2017
 #2
avatar+61 
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no, I was wondering how to solve each of the three, sorry for the confusing spacing, old laptop has troubles XD.

how would you find

sin^2(x)

because you can't just square the answer, and I forgot the proof

brkr19  Feb 27, 2017
 #3
avatar+76953 
0

There's nothing to "solve"....we can just express each one in numerous ways......for instance....

 

tan^2θ  =  sin^2θ/cos^2θ  =  sec^θ - 1  =  1 / cot^2θ  .....etc.

 

Similarly

 

sin^2θ cos^2θ  =  (1/4) [sin(2θ)]^2 =   sin^2θ [ 1 - sin^2θ] = sin^2θ - sin^4θ  .....etc.

 

 

cool cool cool

CPhill  Feb 27, 2017

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