how do I find \(tan^2\theta\)
\(sin^2\theta \)\(cos^2\theta \)
Are you dividing these, brkr19 ???
no, I was wondering how to solve each of the three, sorry for the confusing spacing, old laptop has troubles XD.
how would you find
because you can't just square the answer, and I forgot the proof
There's nothing to "solve"....we can just express each one in numerous ways......for instance....
tan^2θ = sin^2θ/cos^2θ = sec^θ - 1 = 1 / cot^2θ .....etc.
sin^2θ cos^2θ = (1/4) [sin(2θ)]^2 = sin^2θ [ 1 - sin^2θ] = sin^2θ - sin^4θ .....etc.