+0

# Precalculus

0
134
3

Factor and express the answer as a quotient with positive exponents.

x^(-2)-4x^(-5)+3x^(-8)

Thank you!!

Guest Aug 30, 2017
Sort:

#1
+91469
+2

Factor and express the answer as a quotient with positive exponents.

x^(-2)-4x^(-5)+3x^(-8)

$$x^{-2}-4x^{-5}+3x^{-8}\\ =x^{-8}(x^6-4x^3+3)\\ =\frac{x^6-4x^3+3}{x^8}$$

Melody  Aug 30, 2017
#2
+18829
+1

Factor and express the answer as a quotient with positive exponents.

x^(-2)-4x^(-5)+3x^(-8)

$$\begin{array}{|rcll|} \hline && x^{-2}-4x^{-5}+3x^{-8} \\ &=& x^{-8}\left( \frac{x^{-2}} {x^{-8}} - \frac{4x^{-5}} {x^{-8}} +3 \frac{ x^{-8} } {x^{-8}} \right) \\ &=& x^{-8} ( x^{-2} x^{8} - 4x^{-5} x^{8} +3 ) \\ &=& x^{-8} ( x^{-2+8} - 4x^{-5+8} +3 \\ &=& x^{-8} ( x^{6} - 4x^{3} +3 ) \\ &=& x^{-8} (x^3-1)(x^3-3) \\ &=& \dfrac{(x^3-1)(x^3-3)}{x^{8}} \\ \hline \end{array}$$

heureka  Aug 30, 2017
#3
+81049
+1

[ ( x^3 - 1) ( x^3 - 3 ) ]           [ ( x - 1) (x^2 + x + 1 ) ( x^3 - 3) ]

_________________   =      __________________________

x^8                                                  x^8

CPhill  Aug 30, 2017

### 13 Online Users

We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details