\(\frac{\left(\frac{\left(a^nb-ab^n\right)}{2n}\right)}{3\left(a+b\right)}\)

For a and b being integers, when the result of the expression above is an integer, and n is not equal to a + b, I perdict that:

- n is prime;

- n isn't 2.

Can you prove or counter my prediction?

(a, b, n having different names implies that they have different values)

Guest Jan 24, 2018

edited by
Guest
Jan 24, 2018

edited by Guest Jan 24, 2018

edited by Guest Jan 24, 2018

edited by Guest Jan 24, 2018

edited by Guest Jan 24, 2018