If two (positive) prime numbers are roots of the equation x^2 - 19x + k = 0, what is the value of k?

Guest Oct 20, 2020

#1**0 **

Prime numbers that can be added or substracted to obtain -19 are:

-17 and -2.

This factors into

(x-17)(x-2) which would be the same as

x^2-19x+34.

So, k=34.

CalTheGreat Oct 20, 2020

#2**0 **

*If two (positive) prime numbers are roots of the equation x^2 - 19x + k = 0, what is the value of k?*

The only prime numbers I can think of that work are –2 and –17. That would make **K = 34**.

People sometimes forget that 2 is a prime number, they overlook it because it's even.

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Guest Oct 20, 2020