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If two (positive) prime numbers are roots of the equation x^2 - 19x + k = 0, what is the value of k?

 Oct 20, 2020
 #1
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Prime numbers that can be added or substracted to obtain -19 are:

 

-17 and -2.

 

This factors into

(x-17)(x-2) which would be the same as

x^2-19x+34.

 

So, k=34.

 Oct 20, 2020
 #2
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If two (positive) prime numbers are roots of the equation x^2 - 19x + k = 0, what is the value of k?   

 

The only prime numbers I can think of that work are –2 and –17.  That would make K = 34.  

 

People sometimes forget that 2 is a prime number, they overlook it because it's even.  

.

 Oct 20, 2020

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