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A rectangular prism has a length of $3$, a width of $5$, and a height of $11$. What is the distance between two opposite corners of the prism?

 Mar 19, 2024

Best Answer 

 #1
avatar+45 
+2

Easy,

 

The distance is:

 

\(\sqrt{3^2+5^2}\)

 

from length to width

 

\(\sqrt{\sqrt{3^2+5^2}^2+11^2}\)

from length, to width, to hight

 

which simplifies to

 

\(\sqrt{155}\)

 Mar 19, 2024
 #1
avatar+45 
+2
Best Answer

Easy,

 

The distance is:

 

\(\sqrt{3^2+5^2}\)

 

from length to width

 

\(\sqrt{\sqrt{3^2+5^2}^2+11^2}\)

from length, to width, to hight

 

which simplifies to

 

\(\sqrt{155}\)

hasAquestion Mar 19, 2024

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