A rectangular prism has a length of $3$, a width of $5$, and a height of $11$. What is the distance between two opposite corners of the prism?

parmen Mar 19, 2024

#1**+2 **

Easy,

The distance is:

\(\sqrt{3^2+5^2}\)

from length to width

\(\sqrt{\sqrt{3^2+5^2}^2+11^2}\)

from length, to width, to hight

which simplifies to

\(\sqrt{155}\)

hasAquestion Mar 19, 2024

#1**+2 **

Best Answer

Easy,

The distance is:

\(\sqrt{3^2+5^2}\)

from length to width

\(\sqrt{\sqrt{3^2+5^2}^2+11^2}\)

from length, to width, to hight

which simplifies to

\(\sqrt{155}\)

hasAquestion Mar 19, 2024