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What is the probability of at least 10 consecutive heads in 162 tosses of a fair coin?

 Sep 9, 2016
 #1
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The probability is ≈0.0727859 x 100 ~7.28%

 Sep 10, 2016
 #2
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What is the probability of at least 10 consecutive heads in 162 tosses of a fair coin?

 

The prob that the first 10 are all heads is        1 / (2^10)

 

There are 152  possible runs of 10   so that is   152 / (2^10)

 

Probability is around                           152/(2^10) = 0.1484375

 

The probability is really different than this beacuse I think i have done some multiple counting here.  ://   crying

 Sep 11, 2016
 #3
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sequence of coin flips | number of flips | 162
consecutive heads | 10

 

831067990203960713963382614479112849637554279 /

11417981541647679048466287755595961091061972992≈0.0727859=~ 7.28%

http://www.wolframalpha.com/input/?i=1+coin+162+flips,+10+consecutive+heads%3F

 Sep 11, 2016
 #4
avatar+118656 
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ok you are right       frown

 

- the maths to do it without a program like Wolfram Alpha would be very long and involved.

Melody  Sep 11, 2016
 #5
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The probability is: 2^162 - The 162nd term of the " Decanacci Series" [5420499738339183787265487432251826299609302381056]=

 

425506810984427885549251898613305779014427790848 / (2^162) =0.0727859 =~ 7.28%

 Sep 11, 2016

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