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Paula is going to grab 2 balls out of a bag, not replacing the ball after choosing it. There are 3 blue balls, 12 red balls, and 8 purple balls. Now what is the probability of choosing a blue ball then a red ball? Simplify if necessary. Also answer the problem in fraction form.

 Aug 21, 2018
edited by OwenT154  Aug 21, 2018
 #1
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+2

The total number of balls is 23. The probability of choosing a blue ball on her first draw is 3/23. The probabilty of choosing a red ball on her second draw is 12/22, or 6/11, because the ball is not replaced. Now we can multiply the probabilities and get \(3\over 4\)*\(6\over11\), equaling 18/44, or 9/22.

 Aug 21, 2018
 #2
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+1

Well... no. 3/4 wasn't a value in the equation. I thought you had it, try again!

OwenT154  Aug 21, 2018
 #3
avatar+196 
+2

Ah, my bad.

3/23*6/11 = 18/253

 Aug 21, 2018
 #4
avatar+190 
+1

Yea you got it LOL!

OwenT154  Aug 21, 2018
 #5
avatar+196 
+1

cheeky LOL!

 Aug 21, 2018

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