We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
0
197
5
avatar+209 

Paula is going to grab 2 balls out of a bag, not replacing the ball after choosing it. There are 3 blue balls, 12 red balls, and 8 purple balls. Now what is the probability of choosing a blue ball then a red ball? Simplify if necessary. Also answer the problem in fraction form.

 Aug 21, 2018
edited by OwenT154  Aug 21, 2018
 #1
avatar+196 
+2

The total number of balls is 23. The probability of choosing a blue ball on her first draw is 3/23. The probabilty of choosing a red ball on her second draw is 12/22, or 6/11, because the ball is not replaced. Now we can multiply the probabilities and get \(3\over 4\)*\(6\over11\), equaling 18/44, or 9/22.

 Aug 21, 2018
 #2
avatar+209 
+1

Well... no. 3/4 wasn't a value in the equation. I thought you had it, try again!

OwenT154  Aug 21, 2018
 #3
avatar+196 
+2

Ah, my bad.

3/23*6/11 = 18/253

 Aug 21, 2018
 #4
avatar+209 
+1

Yea you got it LOL!

OwenT154  Aug 21, 2018
 #5
avatar+196 
+1

cheeky LOL!

 Aug 21, 2018

15 Online Users

avatar
avatar