Paula is going to grab 2 balls out of a bag, not replacing the ball after choosing it. There are 3 blue balls, 12 red balls, and 8 purple balls. Now what is the probability of choosing a blue ball then a red ball? Simplify if necessary. Also answer the problem in fraction form.
The total number of balls is 23. The probability of choosing a blue ball on her first draw is 3/23. The probabilty of choosing a red ball on her second draw is 12/22, or 6/11, because the ball is not replaced. Now we can multiply the probabilities and get \(3\over 4\)*\(6\over11\), equaling 18/44, or 9/22.
Ah, my bad.
3/23*6/11 = 18/253