+0

# Probability Challenge

0
290
5
+209

Paula is going to grab 2 balls out of a bag, not replacing the ball after choosing it. There are 3 blue balls, 12 red balls, and 8 purple balls. Now what is the probability of choosing a blue ball then a red ball? Simplify if necessary. Also answer the problem in fraction form.

Aug 21, 2018
edited by OwenT154  Aug 21, 2018

#1
+203
+2

The total number of balls is 23. The probability of choosing a blue ball on her first draw is 3/23. The probabilty of choosing a red ball on her second draw is 12/22, or 6/11, because the ball is not replaced. Now we can multiply the probabilities and get $$3\over 4$$*$$6\over11$$, equaling 18/44, or 9/22.

Aug 21, 2018
#2
+209
+1

Well... no. 3/4 wasn't a value in the equation. I thought you had it, try again!

OwenT154  Aug 21, 2018
#3
+203
+2

3/23*6/11 = 18/253

Aug 21, 2018
#4
+209
+1

Yea you got it LOL!

OwenT154  Aug 21, 2018
#5
+203
+1

LOL!

Aug 21, 2018