A pair of standard six-sided die are rolled. The probability that the digits rolled can be arranged to form a two-digit perfect square is
(A) 1/9 (B) 2/9 (C) 7/36 (D) 1/4 (E) 1/3
A pair of standard six-sided die are rolled. The probability that the digits rolled can be arranged to form a two-digit perfect square is
(A) 1/9 (B) 2/9 (C) 7/36 (D) 1/4 (E) 1/3
The 2-digit perfect squares that can be made are 16, 25, 36, 64
1,1 1,2 1,3 1,4 1,5 1,6
2,1 2,2 2,3 2,4 2,5 2,6
3,1 3,2 3,3 3,4 3,5 3,6
4,1 4,2 4,3 4,4 4,5 4,6
5,1 5,2 5,3 5,4 5,5 5,6
6,1 6,2 6,3 6,4 6,5 6,6
So there are eight rolls that will give you the necessary digits, out of thirty-six possible rolls.
8/36 = 2/9 so the answer is (B).
.
