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Thanks please answer as soon as possible!!!!

 Jan 26, 2019
 #1
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\(P[\text{at least 2 consecutive tosses have same number}] = \\ 1-P[\text{no consecutive tosses have same number}] = \\ 1-\dfrac{6\cdot 5^4}{6^5} =\\ 1- \dfrac{625}{1296} = \\ \dfrac{671}{1296}\)

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 Jan 26, 2019

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