hi, tom chooses either an apple, an orange or a pear.
the probability that he chooses an apple is 0.6.
the probability that he chooses an orange is 0.3.
find the probabilty that
(a) he does not choose an apple
(b) he chooses a pear.
thx
+71 Now the probability that he either chooses an apple or not an apple is 1. Now if you subtract the probability that he does choose an apple you are left with the probability that he does not. In this case there is a .6 probability that he does choose an apple, so 1-.6 = a .4 chance that he does not choose an apple. Now next we tackle the pear question. Again there is the probability of 1 that he chooses something. If we subtract the probability of that thing not being a pear we get the probability of the pear. So 1- 0.6- 0.3 = .1 change that he chooses a pear.
So:
A) .4 Chance (40%)
and
B) .1 Chance (10%)
Hope this helps you.
-G
