+0  
 
+5
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avatar+8453 

A card is drawn at random from a pack of 52 playing cards(\(\clubsuit \diamondsuit \heartsuit \spadesuit\)) (without Jokers). What is the probability of getting a card which is neither a 6 nor a \(\heartsuit\)?

 

PS: I typed the suits in LaTeX just for creativity :P

 Jul 2, 2016

Best Answer 

 #2
avatar+112458 
+15

Thanks Solveit

That is a good answer - I'd be inclined to keep your answer exact though.  

 

36/52 = 9/13

 

Thanks to you too Max, I have not seen the card suits pictured in LaTex before - I will put that in the LaTex thread that we keep with the sticky topics :))

 Jul 2, 2016
 #1
avatar+2533 
+13

i think:

 

minus all the cards with heart on it:

52*(3/4)=39

 

minus all the cards with 6:

39-3=36 (3 because we already have minused one 6 with heart on it)

 

The probability: 36/52 = 0.6923076923076923(70%)

 Jul 2, 2016
 #2
avatar+112458 
+15
Best Answer

Thanks Solveit

That is a good answer - I'd be inclined to keep your answer exact though.  

 

36/52 = 9/13

 

Thanks to you too Max, I have not seen the card suits pictured in LaTex before - I will put that in the LaTex thread that we keep with the sticky topics :))

Melody Jul 2, 2016
 #3
avatar+112458 
+10

Here it is in the LaTex thread :))

 

http://web2.0calc.com/questions/latex#r73

 Jul 2, 2016

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