+0  
 
+5
581
3
avatar+7220 

A card is drawn at random from a pack of 52 playing cards(\(\clubsuit \diamondsuit \heartsuit \spadesuit\)) (without Jokers). What is the probability of getting a card which is neither a 6 nor a \(\heartsuit\)?

 

PS: I typed the suits in LaTeX just for creativity :P

 Jul 2, 2016

Best Answer 

 #2
avatar+97561 
+15

Thanks Solveit

That is a good answer - I'd be inclined to keep your answer exact though.  

 

36/52 = 9/13

 

Thanks to you too Max, I have not seen the card suits pictured in LaTex before - I will put that in the LaTex thread that we keep with the sticky topics :))

 Jul 2, 2016
 #1
avatar+2496 
+13

i think:

 

minus all the cards with heart on it:

52*(3/4)=39

 

minus all the cards with 6:

39-3=36 (3 because we already have minused one 6 with heart on it)

 

The probability: 36/52 = 0.6923076923076923(70%)

 Jul 2, 2016
 #2
avatar+97561 
+15
Best Answer

Thanks Solveit

That is a good answer - I'd be inclined to keep your answer exact though.  

 

36/52 = 9/13

 

Thanks to you too Max, I have not seen the card suits pictured in LaTex before - I will put that in the LaTex thread that we keep with the sticky topics :))

Melody Jul 2, 2016
 #3
avatar+97561 
+10

Here it is in the LaTex thread :))

 

http://web2.0calc.com/questions/latex#r73

 Jul 2, 2016

34 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.