A bag contains 6 red marbles, 5 blue marbles and 8 green marbles. If three marblesare drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be green?
\(6 \over 19\) chance for the first marble
\(5 \over 19\) chance for the second marble
\(8 \over 19 \) chance for the third marble.
Because they all "rely" on each other, the probability is the product of all 3 cases.