Calamitous Clod rolls a pair of rigged dice. The probability of rolling k on a die is directly proportional to k. What is the probability that the sum of Calamitous Clod's dice is equal to 3?
I assume the dice are cubes, (6 sides)
The numbers on them are 1 to 6
1+2+3+4+5+6= 21
so prob of rolling a 1 is 1/21
so prob of rolling a 2 is 2/21
etc
To roll a 3 you have to have (1,2) ot (2,1)
P(rolling 1 followed by 2 )= 1/21 * 2/21 = 3/441
P(rolling 2 followed by 1)= 1/21 * 2/21 = 3/441
So prob of rolling a total of 3 is 6/441 = 2/147