+0  
 
0
41
1
avatar

Calamitous Clod rolls a pair of rigged dice. The probability of rolling k on a die is directly proportional to k. What is the probability that the sum of Calamitous Clod's dice is equal to 3?

 Jul 1, 2022
 #1
avatar+117752 
+1

I assume the dice are cubes, (6 sides)

The numbers on them are 1 to 6

 

 

1+2+3+4+5+6= 21     

so prob of rolling a 1 is  1/21

so prob of rolling a 2 is  2/21

etc

 

To roll a 3 you have to have (1,2)  ot (2,1)

P(rolling 1 followed by 2 )= 1/21 * 2/21 = 3/441

P(rolling 2 followed by 1)= 1/21 * 2/21 = 3/441

 

So prob of rolling a total of 3 is   6/441  = 2/147

 Jul 1, 2022

9 Online Users