Two fair, six-sided dice are rolled. They are marked so one die has the numbers 1, 3, 5, 7, 9, 11 and the other has the numbers 2, 4, 6, 8, 10, 12. What is the probability that the sum of the numbers rolled is divisible by 5? Express your answer as a common fraction.

Guest Aug 5, 2022

#1**+1 **

(3, 5, 5, 7, 7, 7, 9, 9, 9, 9, 11, 11, 11, 11, 11, 13, 13, 13, 13, 13, 13, 15, 15, 15, 15, 15, 17, 17, 17, 17, 19, 19, 19, 21, 21, 23)>>Total = 36

**The probability is ==7 / 36**

Guest Aug 6, 2022

#2**+1 **

**STRANGE DICE, DIVISIBLE BY 5**

Two fair, six-sided dice are rolled. They are marked so that one die has the numbers 1, 3, 5, 7, 9, 11

and the other has the numbers 2, 4, 6, 8, 10, 12. What is the probability that the sum of the numbers rolled

is divisible by 5? Express your answer as a common fraction.

**All possible sums:**

[3, 5, 7, 9, 11, 13, 5, 7, 9, 11, 13, 15, 7, 9, 11, 13, 15, 17, 9, 11, 13, 15, 17, 19, 11, 13, 15, 17, 19, 21, 13, 15, 17, 19, 21, 23]

**I count: 36**

**All in there that are divisible by 5:**

[5, 5, 15, 15, 15, 15, 15]

**I count 7**

**The probability as a fraction: **\(\frac{7}{36}\)* If Your brain hurts, use python*

tuffla2022 Aug 6, 2022

edited by
tuffla2022
Aug 6, 2022

edited by tuffla2022 Aug 6, 2022

edited by tuffla2022 Aug 6, 2022

edited by tuffla2022 Aug 6, 2022

edited by tuffla2022 Aug 6, 2022

edited by tuffla2022 Aug 6, 2022

edited by tuffla2022 Aug 6, 2022