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Two fair, six-sided dice are rolled. They are marked so one die has the numbers 1, 3, 5, 7, 9, 11 and the other has the numbers 2, 4, 6, 8, 10, 12. What is the probability that the sum of the numbers rolled is divisible by 5? Express your answer as a common fraction.

 
 Aug 5, 2022
 #1
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(3, 5, 5, 7, 7, 7, 9, 9, 9, 9, 11, 11, 11, 11, 11, 13, 13, 13, 13, 13, 13, 15, 15, 15, 15, 15, 17, 17, 17, 17, 19, 19, 19, 21, 21, 23)>>Total = 36

 

 

The probability is ==7 / 36

 
 Aug 6, 2022
 #2
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STRANGE DICE, DIVISIBLE BY 5

Two fair, six-sided dice are rolled. They are marked so that one die has the numbers 1, 3, 5, 7, 9, 11
and the other has the numbers 2, 4, 6, 8, 10, 12. What is the probability that the sum of the numbers rolled
is divisible by 5? Express your answer as a common fraction.

 

All possible sums:
 [3, 5, 7, 9, 11, 13, 5, 7, 9, 11, 13, 15, 7, 9, 11, 13, 15, 17, 9, 11, 13, 15, 17, 19, 11, 13, 15, 17, 19, 21, 13, 15, 17, 19, 21, 23] 
I count: 36


All in there that are divisible by 5:
 [5, 5, 15, 15, 15, 15, 15]
I count 7


The probability as a fraction:  \(\frac{7}{36}\)  If Your brain hurts, use python

 

https://www.online-python.com/s7qZVQRT36

 
 Aug 6, 2022
edited by tuffla2022  Aug 6, 2022
edited by tuffla2022  Aug 6, 2022
edited by tuffla2022  Aug 6, 2022
edited by tuffla2022  Aug 6, 2022

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