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# Probability Statistics

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The mean number of accidents in a shoe factory is 0.10 per day. What is the probability that during a randomly selected day, there will be:

a) no accidents

b) exactly 1 accident

c) at least 1 accident

Sep 17, 2016

#1
+27470
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The Poisson distribution gives the probability of k events in an interval as $$p = \frac{\lambda^ke^{-\lambda}}{k!}$$ where $$\lambda$$  is the mean.

So:

1. $$p(k=0)=e^{-0.1} \rightarrow 0.905$$

2. $$p(k=1)=0.1e^{-0.1} \rightarrow 0.0905$$

3. Ther probability of at least one accident is 1 - (the probability of exactly no accidents plus the probability of exactly one accident).

Sep 17, 2016

#1
+27470
+10

The Poisson distribution gives the probability of k events in an interval as $$p = \frac{\lambda^ke^{-\lambda}}{k!}$$ where $$\lambda$$  is the mean.

So:

1. $$p(k=0)=e^{-0.1} \rightarrow 0.905$$

2. $$p(k=1)=0.1e^{-0.1} \rightarrow 0.0905$$

3. Ther probability of at least one accident is 1 - (the probability of exactly no accidents plus the probability of exactly one accident).

Alan Sep 17, 2016