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On a shelf, there is space for three books, but there are five books that should be arranged. The books are numbered 1, 2, 3, 4, 5. A student has to choose three out of five books to arrange on the shelf. What is the probability that he chooses Book 3 at the first position?

 Feb 11, 2017
 #1
avatar+118687 
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one in five

 

\(\frac{1}{5}\)

 Feb 11, 2017
 #2
avatar+129899 
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To see Melody's answer....

 

The possible number of  sets consist of the possible permutes of choosing any 3 of the 5 books  =  P(5,3)  = 60

 

We want to choose the sets    {3, a, b}    where a,b  are the possible permutes  of choosing two of the other 4 books  = P(4,2)  = 12

 

So....12 / 60   = 1 / 5  .

 

 

cool cool cool

 Feb 11, 2017
 #3
avatar+118687 
+5

I didn't do it like that Chris,

 

I just said there are 5 books, any of them could be in the first position so the probability that any in particular one is first is 1 in 5.

 

Easy peazy :))

Melody  Feb 11, 2017

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